194 lines
7.4 KiB
Prolog
194 lines
7.4 KiB
Prolog
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* B U C K A R O O B A N Z A I *
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* aka the Reset Vector *
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* *
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* presents *
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* *
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* Cracking On the IBMpc *
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* Part I *
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* *
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****************************************
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Introduction
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------------
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For years, I have seen cracking tutorials for the APPLE computers, but never
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have I seen one for the PC. I have decided to try to write this series to help
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that pirate move up a level to a crackest.
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In this part, I will cover what happens with INT 13 and how most copy
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protection schemes will use it. I strongly suggest a knowledge of Assembler
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(M/L) and how to use DEBUG. These will be an important figure in cracking
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anything.
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INT-13 - An overview
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--------------------
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Many copy protection schemes use the disk interrupt (INT-13). INT-13 is
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often use to either try to read in a illegaly formated track/sector or to
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write/format a track/sector that has been damaged in some way.
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INT-13 is called like any normal interupt with the assembler command INT 13
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(CD 13). [AH] is used to select which command to be used, with most of the
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other registers used for data.
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INT-13 Cracking Collage
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-----------------------
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Although, INT-13 is used in almost all protection schemes, the easiest to
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crack is the DOS file. Now the protected program might use INT-13 to load some
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other data from a normal track/sector on a disk, so it is important to
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determine which tracks/sectors are inportant to the protection scheme. I have
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found the best way to do this is to use LOCKSMITH/pc (what, you don't have LS.
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Contact your local pirate for it.)
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Use LS to to analyze the diskette. Write down any track/sector that seems
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abnormal. These track are must likely are part of the protection routine.
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Now, we must enter debug. Load in the file execute a search for CD 13.
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Record any address show. If no address are picked up, this mean 1 or 2 things,
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the program is not copy protected (bullshit) or that the check is in an other
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part of the program not yet loaded. The latter being a real bitch to find, so
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I'll cover it in part II. There is another choice. The CD 13 might be hidden
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in self changing code. Here is what a sector of hidden code might look like
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-U CS:0000
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1B00:0000 31DB XOR BX,BX
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1B00:0002 8EDB MOV DS,BX
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1B00:0004 BB0D00 MOV BX,000D
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1B00:0007 8A07 MOV AL,[BX]
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1B00:0009 3412 XOR AL,12
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1B00:000B 8807 MOV [BX],AL
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1B00:000D DF13 FIST WORD...
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In this section of code, [AL] is set to DF at location 1B00:0007. When you
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XOR DF and 12, you would get a CD(hex) for the INT opcode which is placed right
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next to a 13 ie, giving you CD13 or INT- 13. This type of code cann't and will
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not be found using debug's [S]earch command.
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Finding Hidden INT-13s
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----------------------
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The way I find best to find hidden INT-13s, is to use a program called
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PC-WATCH (TRAP13 works well also). This program traps the interrupts and will
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print where they were called from. Once running this, you can just disassemble
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around the address until you find code that look like it is setting up the disk
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interupt.
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An other way to decode the INT-13 is to use debug's [G]o command. Just set a
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breakpoint at the address give by PC-WATCH (both programs give the return
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address). Ie, -G CS:000F (see code above). When debug stops, you will have
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encoded not only the INT-13 but anything else leading up to it.
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What to do once you find INT-13
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-------------------------------
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Once you find the INT-13, the hard part for the most part is over. All that
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is left to do is to fool the computer in to thinking the protection has been
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found. To find out what the computer is looking for, examine the code right
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after the INT-13. Look for any branches having to do with the CARRY FLAG or
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any CMP to the AH register.
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If a JNE or JC (etc) occurs, then [U]nassembe the address listed with the
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jump. If it is a CMP then just read on.
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Here you must decide if the program was looking for a protected track or just
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a normal track. If it has a CMP AH,0 and it has read in a protected track, it
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can be assumed that it was looking to see if the program had successfully
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complete the READ/FORMAT of that track and that the disk had been copied thus
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JMPing back to DOS (usually). If this is the case, Just NOP the bytes for the
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CMP and the corrisponding JMP.
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If the program just checked for the carry flag to be set, and it isn't, then
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the program usually assumes that the disk has been copied. Examine the
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following code
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INT 13 <-- Read in the Sector
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JC 1B00 <-- Protection found
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INT 19 <-- Reboot
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1B00 (rest of program)
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The program carries out the INT and find an error (the illegaly formatted
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sector) so the carry flag is set. The computer, at the next instruction, see
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that the carry flag is set and know that the protection has not been breached.
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In this case, to fool the computer, just change the "JC 1B00" to a "JMP 1B00"
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thus defeating the protection scheme.
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NOTE: the PROTECTION ROUTINE might be found in more than just 1 part of the
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program
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Handling EXE files
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------------------
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As we all know, Debug can read .EXE files but cannot write them. To get
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around this, load and go about cracking the program as usual. When the
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protection scheme has been found and tested, record (use the debug [D]ump
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command) to save + & - 10 bytes of the code around the INT 13.
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Exit back to dos and rename the file to a .ZAP (any extention but .EXE will
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do) and reloading with debug.
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Search the program for the 20+ bytes surrounding the code and record the
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address found. Then just load this section and edit it like normal.
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Save the file and exit back to dos. Rename it back to the .EXE file and it
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should be cracked. ***NOTE: Sometimes you have to fuck around for a while to
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make it work.
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DISK I/O (INT-13)
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-----------------
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This interrupt uses the AH resister to select the function to be used. Here
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is a chart describing the interrupt.
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AH=0 Reset Disk
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AH=1 Read the Status of the Disk
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system in to AL
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AL Error
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----------------------------
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00 - Successful
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01 - Bad command given to INT
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*02 - Address mark not found
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03 - write attempted on write prot
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*04 - request sector not found
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08 - DMA overrun
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09 - attempt to cross DMA boundry
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*10 - bad CRC on disk read
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20 - controller has failed
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40 - seek operation failed
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80 - attachment failed
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(* denotes most used in copy protection)
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AH=2 Read Sectors
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input
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DL = Drive number (0-3)
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DH = Head number (0or1)
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CH = Track number
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CL = Sector number
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AL = # of sectors to read
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ES:BX = load address
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output
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AH =error number (see above)
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[Carry Flag Set]
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AL = # of sectors read
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AH=3 Write (params. as above)
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AH=4 Verify (params. as above -ES:BX)
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AH=5 Format (params. as above -CL,AL
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ES:BX points to format
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Table)
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For more infomation on INT-13 see the IBM Techinal Reference Manuals.
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Comming Soon
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------------
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In part II, I will cover CALLs to INT-13 and INT-13 that is located in
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diffrents overlays of the program
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Happy Cracking.....
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Buckaroo Banzai
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<-------+------->
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PS: This Phile can be Upload in it's
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unmodified FORM ONLY.
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PPS: Any suggestion, corrections, comment on this Phile are accepted and
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incouraged.....
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