99 lines
4.5 KiB
Plaintext
99 lines
4.5 KiB
Plaintext
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______________________________________________________________________________
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| File Name : PUMPFE.ASC | Online Date : 10/15/94 |
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| Contributed by : Frode Olsen | Dir Category : ENERGY |
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| From : KeelyNet BBS | DataLine : (214) 324-3501 |
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| KeelyNet * PO BOX 870716 * Mesquite, Texas * USA * 75187 |
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| A FREE Alternative Sciences BBS sponsored by Vanguard Sciences |
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|----------------------------------------------------------------------------|
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This excellent file also has an image called PUMPFE.GIF that you should take.
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If you took this down as PUMPFE.ZIP, you will have the .ASC AND .GIF file.
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Otherwise, you only took it down as PUMPFE.ASC then you should also get .GIF.
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Newton - engine follow-up
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How to use a constant force to build a practical Perpetuum Mobile
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To begin with this is the second text on the more general Newton Engine
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principle. The first text describes an implementation with electronic
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components.
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The method described in this text attempts to build a case for the Perpetuum
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Mobile using no more than Isaac Newton's formulas for Energy and Distance.
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Indeed, the very science that holds the Perpetuum Mobile to be impossible,
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also use these formulas as fundaments
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We will use a standard commercially available bilge pump, a rotor plate of
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radius 1/2 meter.
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Pump parameters: Pin = 210 Watts
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Q = 4000 liters/hour at 2m elevation = 1,1 Liters/sec
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Tube diam = 1 inch = 2,54 Cm = 0,254 dm
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All we now have to do is to find the constant FORCE that this pump will give.
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Then we place a tube on the rotor so that the water flows radially out towards
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the periphery, and finally the tube is bent so that the water is expelled
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backwards compared with the direction of rotation. This then produces the
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forward thrust we need.
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We find this FORCE to be:
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Pressure P = Tube Volume * Water Density / Tube Area
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= Phi * (0,254/2)^2 * 20 dm * 1(Kg/dm^3) / Phi * (0,254/2)^2
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= 20 [Kg/dm^3]
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FORCE F = Pressure * Area tube = 20 [Kg/dm^3] * Phi * (0,254/2)^2
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= 1 Kg = 10 [N]
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This thrust force is a minimum for the pump, because it is calculated for an
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elevation of 2 meters, or 20 dm.
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Now we can use Newton's formulas to find what amount of POWER we can get
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(load) from the rotor at a particular rotational speed:
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Kinetic Energy Ek = Force * Distance = F * S [Joule]
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S = V * t [m]
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Ek = F * S = F * ( v * t ) = F * v * t
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Power P = Ek / t = F * v * t / t = F * V [Watt]
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From this simple formula we see that with a constant force that does not
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depend on the speed, the output Power is directly proportional with the speed
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at the periphery.
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This is important, because it means that regardless of what amount of constant
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input power is required to produce the constant force, the output power can
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always be made larger than the input by increasing the speed sufficiently.
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At what speed will we have equal output and input power, or 'break-even'?
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In our example we have an input power of 210 Watts. Lets do the calculation:
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Po = Pi F * V = 210 10 * V = 210 V = 210 / 10 = 21[m/s]
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We see that it will require a peripheral speed of 21 m/s to 'break-even'. This
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equals different RPM's depending on the rotor radius:
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Rotor Radius 0,25 0,5 1 [Meter]
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RPM 800 400 200 [RPM]
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The input power of 210 Watts would have to be supplied all the time. What if
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we supplied it from a generator driven by the spinning rotor? The 210 Watts
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would then have to subtracted from the output power we found earlier:
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Available output Pn = Po - Pi = 10 [N] * V[m/s] - 210
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= 0,53 * RPM - 210 [Watt]
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At 400 RPM's all the output is used to drive the pump. At lower RPM's the
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device uses more power than it produces. But, at RPM's above 400 RPM's it will
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start producing surplus power whilst being self-supplied with drive power.
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E.g. at 800 RPM's it would give 210 Watts available output to be spent, whilst
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at the same time feeding back 210 watts to drive the bilge pump.
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The Norwegian Free Energy Group
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